3y^2-3y^(1/2)=0

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Solution for 3y^2-3y^(1/2)=0 equation:


D( y )

y < 0

y < 0

y in <0:+oo)

3*y^2-(3*y^(1/2)) = 0

3*y^2-3*y^(1/2) = 0

t_1 = y^(1/2)

3*t_1^4-3*t_1^1 = 0

3*t_1^4-3*t_1 = 0

3*t_1*(t_1^3-1) = 0

1*t_1^3 = 1 // : 1

t_1^3 = 1

t_1^3 = 1 // ^ 1/3

t_1 = 1

3*t_1 = 0

3*t_1 = 0 // : 3

t_1 = 0

t_1 = 1

y^(1/2)-1 = 0

1*y^(1/2) = 1 // : 1

y^(1/2) = 1

y^(1/2) = 1 // ^ 2

y = 1

t_1 = 0

y^(1/2)+0 = 0

y^(1/2) = 0

1*y^(1/2) = 0 // : 1

y^(1/2) = 0

y = 0

y in { 1, 0 }

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